I made this when I couldn't find a way to get the square root of a number in MUGEN(during play) for a piece of code that uses Pythagorean Theorem. I'm new to MUGEN coding so if there is an easier way please let me know! -Edit-Just found this... which is probably a better bet than the code below. http://mugenguild.com/forum/topics/square-roots-and-general-roots-mugen--6588.msg64497.html#msg64497My notes:Code: ;==========================================================================;Inktrebuchet ;Square Root Calculator 3/28/2017 ;========================================================================== ;==========================================================================;Goal:;-Find Square Root;;notes:;Number you want square root of goes in var(1);Square root of number is var(7);;-------------------------------------------------------------------------- ;==========================================================================; AI Enemy Combo Count System Helper Initialization;==========================================================================; Variable usage:; This is a record of the variables that are used;; var(1) - Number you want to find Square Root of; var(2) - ; var(3) - ; var(4) - ; var(5) - ; var(6) - ; var(7) - Square Root of number;--------------------------------------------------------------------------;===========================================================;Find Square Root;===========================================================[state n] ; area (value to find square root of)type = varsettrigger1 = 1v = 1value = 25;persistent = 0ignorehitpause = 1[state n] ; add 1 every 2 ticks. and side 4type = varaddtrigger1 = gametime%2=0trigger1 = var(3) <= var(1)v = 2value = 1;persistent = 0ignorehitpause = 1[state n] ; areatype = varaddtrigger1 = var(3) <= var(1) ;has reached areav = 3value = var(2);persistent = 0ignorehitpause = 1;>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>[state n] ; side 3 and 2type = varsettrigger1 = var(3) >= var(1) ;has reached areav = 4value = var(2)-1;persistent = 0ignorehitpause = 1[state n] ; side 1type = varsettrigger1 = var(3) >= var(1) ;has reached areav = 5value = var(2)-2;persistent = 0ignorehitpause = 1;>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>[state n] ; perimetertype = varsettrigger1 = var(3) >= var(1) ;has reached areav = 6value = var(5)+var(4)+var(4)+var(2) + 4 ; All sides + number of sides.;persistent = 0ignorehitpause = 1[state n] ; square root of area*(var(1))type = varsettrigger1 = var(3) >= var(1) ;has reached areav = 7value = var(6)/4 ; perimeter divided by number of sides.;persistent = 0ignorehitpause = 1

x ** 1/2 is the square root of x.There's many methods of calculating a square root: trigonometric, exponential, approximating via series, etc. If you ever make use of the exponential or trigonometric functions while you calculate it, you will end up with the same result.I advice against wasting variables for doing this.

Thank you for sharing that one! I just found http://mugenguild.com/forum/topics/square-roots-and-general-roots-mugen--6588.msg64497.html#msg64497 recently too.My ignorance of mugen code fueled this one. It was fun anyways.Hopefully this thread will help anyone trying to find square root functions, find them a little easier.

For a fun exercise, I came up with another way of calculating a square root after reading this thread. This is based on an old geometric construction by Euclides (I believe).sqrt(x) = ((x+1.0)/2.0)*sin(acos((x-1.0)/(x+1.0)))x should be written in float form.

A re-discovery on my part then, I just made this up at my desk after no luck searching for solutions online. hahaI am very impressed to see your formula do the same work! Thank you for sharing it here.